2x^2-1962=0

Solution for 2x^2-1962=0 equation:

2x^2-1962=0

a = 2; b = 0; c = -1962;
Δ = b2-4ac
Δ = 02-4·2·(-1962)
Δ = 15696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15696}=\sqrt{144*109}=\sqrt{144}*\sqrt{109}=12\sqrt{109}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{109}}{2*2}=\frac{0-12\sqrt{109}}{4}
=-\frac{12\sqrt{109}}{4}
=-3\sqrt{109}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{109}}{2*2}=\frac{0+12\sqrt{109}}{4}
=\frac{12\sqrt{109}}{4}
=3\sqrt{109}
$